9x^2-8x-17=0

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Solution for 9x^2-8x-17=0 equation: 



9x^2-8x-17=0

a = 9; b = -8; c = -17;
Δ = b2-4ac
Δ = -82-4·9·(-17)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-26}{2*9}=\frac{-18}{18}
=-1
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+26}{2*9}=\frac{34}{18}
=1+8/9
$

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